Solution / Explanation:Alphabetical order of letters: E, G, G, L, O, O. Words starting with E: $\frac{5!}{2!2!} = 30$. Words starting with G: GE gives $\frac{4!}{2!} = 12$, GG gives 12, GL gives 12. For GO: GOE gives $3! = 6$, GOG gives 6, GOL gives 6, GOOE gives $2! = 2$, GOOGEL gives 1. Total preceding words $= 30 + 12 + 12 + 12 + 6 + 6 + 6 + 2 + 1 = 87$. Rank $= 87 + 1 = 88$.